Recent content by glyon

  1. G

    Is there a shortcut for finding theta4 using Snell's Law when theta2 is known?

    Thanks, I think I figured it out now: theta3 = A - theta2, then do snells law again for theta4.
  2. G

    Is there a shortcut for finding theta4 using Snell's Law when theta2 is known?

    Thanks! Aren't the normal line perpendicular to the prism edges rather than parallel to the rays though? Basically all i want to know is the exit angle for a set incident angle, n1 and n2.
  3. G

    Is there a shortcut for finding theta4 using Snell's Law when theta2 is known?

    Thanks for getting back to me. However, I'm still struggling to see how that third angle is 180-apex. I believe that the relationship between theta2 and theta3 is simply the apex = theta2 + theta3 but I can't see why! Thanks again!
  4. G

    Is there a shortcut for finding theta4 using Snell's Law when theta2 is known?

    Snells Law prism - from theta2 -> theta3? Hi, I was wondering if there's a formula to go straight from theta1 to theta 4, when the apex angle is known. Thanks[PLAIN]http://cord.org/cm/leot/course06_mod07/Fig3.gif My problem is getting from theta2 to theta3. Thanks ps. This is not a homework...
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