Recent content by goatsebear

But then doesn't the x*e^x^2 integrated over dx bring me back to the same problem of being unable to integrate e^x^2?

Okay so I talked to my professor and you can actually do this problem. It has something to do with switching the boundaries. Like instead of having it dxdy, make it dydx and change the boundaries of the integrals using the graph of the region. Since the region is a right triangle with the...

Alright well I guess I'll just have to email my professor and ask him to clarify it.

Honestly, I can't tell. Its a take home test and the subscript goes: e^x^2. Looks to me like its e^(x^2) so that's how I'm going to solve it.

Homework Statement Evaluate \int\int e^x^2 dx dy. The bounds for the inner integral go from y to 1 The bounds for the outer integral go from 0 to 1 2. The attempt at a solution I can easily do this, I just do not see how I can get e^x^2 to integrate for x. Is there some sort of special...

So I was mostly right other than that being (x,0). Now I just plug those points in for x and y in that D = AC - B^2 right? How would I do that with the (x,0) point?

Homework Statement Find the stationary points and local extreme values of f(x,y) = xy^2e^-(\frac{x^2 + y^2)}{2} Homework Equations You need to find the gradient for the function and then set it equal to 0. So then df/dy equals df/dx and you can solve for a solution set.The Attempt at a...

I basically just have to write down the boundary and if the set is open, closed or neither. Thanks for the help.

Alright. So it cannot be open because a circle of points around a point in the set includes points outside of the set. Some of the points are not interior points in it. I guess the point of n = 3 where then it would be 1/3. For closed, since 0 is not in the set, it is not closed. The...

So that would make {1/n} open since it does not its boundary but it does contain the neighborhood of points right?

What do you exactly mean by complement? I have never heard that term before. And looking back at the other questions, I think that the boundary of 2 would be x^2 + y^2 - z \leq 0 which would include all the points on and in the figure.

A set is closed if the set contains its boundary right? A set is open if it contains a neighborhood of each of its points. My professor never really taught this subject well and it is really hard to try and teach this from the book. For the first problem, is my boundary right? I would...

Homework Statement Specify the boundary of the following sets. State whether the sets are open, closed, or neither. 1. {1 / n : n \in N}2. { (x,y,z): x^2 + y^2 = z }3. { (x,y): 0 < x \leq 4, 0 < y \leq 4 }2. The attempt at a solution 1. I want to say that the boundary is where n =/= 0...