Recent content by gozita73

bump ?

cool thanks so much... theta turns out to be around 16.1 degrees doing the rest should be no problem for me thanks again

Fac = 4000N ?

F_{ac}cos(30) - F_{ab}cos(\theta) = 0 F_{ab}cos(\theta) = F_{ac}cos(30) F_{ab} = \frac{F_{ac}cos(30)}{cos(\theta) } therefore...subbing into the other eq. F_{ac}sin(30) + \frac{F_{ac}cos(30)}{cos(\theta) }sin(\theta) = 3000 F_{ac}(sin(30) + cos(30)}tan(\theta))= 3000

ok, so this is the part where I'm completely stuck because there are 3 unknowns... would either Fac or Fab have the maximum tension? that is...either Fac = 4000N or Fab = 4000N?

yep, my bad...that was supposed to be - Fac(sin(30))

ok so 3000 + F_{ac}sin(30) - F_{ab}sin(\theta) = 0 and now i got two equations: 3000 + F_{ac}sin(30) - F_{ab}sin(\theta) = 0 and F_{ac}cos(30) - F_{ab}cos(\theta) = 0 if i make them equal to each other, it seems that i have too many unknowns

ah ok, so: [tex] F_{ac}sin(30) + F_{ab}sin(\theta) - 3000 = 0 [tex] T in the problem opposes the y-components of the Fab and Fac

ah true that's because they have opposite directions right? for the y-components: F_{ac}sin(30) + F_{ab}sin(\theta) + 3000 = 0 is that correct?

I've been staring at those equations for quite a while now... all i can see is that: In the x-axis: Fab cos(theta) = -Fac cos(30) and in the y-axis: 3000N = Fab sin(theta) + Fac sin(30) I know through the sin rule that: sin (theta)/ Fac = sin (30)/Fab but I don't know how the...

so the x component of F1 would be supported by the wall??

I get: Sum of Fx 0 = Fab cos (theta) + Fac cos (30) Sum of Fy 0 = Fab sin (theta) + Fac cos (30) - 3000N Would Fab and Fac equal max. tension (4000N)? otherwise, I'm completely stuck

The space truss showin has compression and tension forces acting in the members as shown. Force F is 10kN, determine the three unknown forces (F1, F2 and F3). I know that it should be the summation of Fx, Fy and Fz, however for F1, there is no reaction force, so I don't know what to...

can anyone help me with this?