Recent content by GrapesOfWrath

It does depend upon what we mean by sea level--usually, that is a datum, and the tides are high or low with respect to it. At the level of detail of the tides (or wind and shore conditions), it's not constant at sea level. But you're right, there are potentials other than gravitational that...

Just because the surface is an equipotential, does not mean that the force or acceleration due to gravity is the same at all points of the surface. In order for the surface to be an equipotential, no energy should be gained in going from one point to another--there would be no flow. The...

I don't think it does assume that. The h's are distinct in the x and z directions (one's perpendicular to the earth/moon line, the other parallel). On the other hand, that page has numerous errors. We were just discussing it over at the Bad Astronomy Bulletin Board. There seems to be at...

Gravity waves? How does that work? :)

Certainly! :smile: The tidal displacement due to the change in the equipotential surface is a little more than a meter--larger tides are due to coastline configurations that cause the tide to be mulitplied (the so-called tidal wave in the Indian Ocean disaster started out as a...

Then that explains it, right? ??

IIRC, the oceans have little to do with it. The solid Earth tidal displacement is about half that of the surface water--so there is a lot more mantle displaced. The tides are symmetrical, but they are displaced from the centerline--they don't arise/subside instantly. The torque on the...

The equalities are the bounding surfaces, and the solution is found on the surface--the vertices, in fact.

The final part? you mean the two equalities?

OK, but remember that your labor hours are no longer limited to 70. I would also not use "z" to represent profit, since you are already using it for product C. :) How about: Maximize: P = x + 9y + 5z - 5u - 15v (profit) subject to: 2x + 3y + 5z <= 70 + u (labor hrs.) x + 4y + 5z <= 45...

Your results (2, 1, 1, 2, 1, 1, 1, 2, ) are OK, I just extended them. The first level differences are just the numbers that were "left out" of the first sequence, the second level differences have a 2 whenever the first level differences skips over a element of the original sequence.

2, 1, 1, 2, 1, 1, 1, 2, 1, 1, 1, 1, 2, ok so far 1, 1, 1, 1, 1, 1, 2 hmm...

are you trying to find a Mathematica command to do that in general, or do you just need that particular function? Couldn't you type in the general definition of the nth Taylor function term?

Let u = additional labor hours, and v = additional machine hours. How do they affect your profit, and how do they affect your constraint functions? Express it algebraically.

Describe the illustration in a little more detail