like rootX said, when dealing with absolute value functions, it's usually best to define it peace-wise.
f(x) = 6x for x >= 0
-6x for x < 0
Or you could notice that the two functions are even, and you could thus solve for x using 6x, and keep in mind that there is...
Thanks for your help.
So it appears that 1.15 cents is correct? I just thought it would cost so much more for all of that work! If you're up to it, would you mind checking if I calculated the work correctly?
Man, calculating work is a ton of work!:eek:
Homework Statement
Gasoline is stored in a cylindrical tank buried on its side, with the highest part of the tank 5 ft below the surface. The tank is 6 ft in diameter and 10 ft long. Density of gasoline is 45 lb/cubic ft. Assume that the filler cap of each automobile gas tank is 2 ft...
This is truly excellent advice. :biggrin:
However, I wouldn't want to "waste" four or more years of my life! Although I would be learning what I love, I have to be at least a little practical. Upon starting college, I wanted to go to med school. I quickly realized, however, that this may...
Yes, I have definitley been told that before, and I certainly have the motivation to learn, but surely it isn't that simple? Although, after thinking about it for a while, I guess there is really no way to know for sure if you can handle it. I have never taken anything like an intelligence...
I'm currently a freshman undergraduate majoring in both math and physics, currently taking: first semester calc, chemistry, biology and english. My dream is to be some type of theoretical physicist. As far back as I can remember, I have always been very interested in science. My parents have...
Hi all, I am looking for some advice on my next semester's schedule; currently planning on double majoring in math and physics.
This semester I am taking...
Calc 1 (the equivalent of calc 1 and about half of calc II at most universities.)
Foundations of chem (typical first course in college...
Ah, I did not even notice that log derivative.
So I would have
\int\frac{1}{x}dx + \int\frac{1}{1-x}dx = ln(abs(x)) - ln(abs(1-x))
ln(abs(x)) - ln(abs(1-x)) = ln(f(x)) = ln(abs(x/(1-x)))
f(x) = e^{ln(abs(x/(1-x)))} = abs(x/(1-x)) + C ?
Wow, thank you guys for the quick replies.
Fortunatly, we just started learning antiderivatives and the basics of integrals in class the end of last week. UNfortunatly, we haven't gone over differential equations with integrals. It appears that I need to find the antiderivative of 1 /...
Hello everyone, first time poster here. I've been a lurker for about a week, but finally decided to join because I cannot for the life of me figure out this problem.
Homework Statement
Zach has trouble with the Quotient Rule; he thinks that d/dx (f(x)/g(x)) =
f′(x)/g′(x). On his last...