Recent content by GreyNoise

Got it fresh_42! Thnx

Where is "here" fresh_42? I tried from the page where this thread appears (is that what you meant?). It took me to the article, but I can't find a link to comments from there.

Does anyone know how to leave comments for an Insight Article? I wanted to comment and ask a question, but I can't find a link (not obvious to me anyway). At the bottom it reads to login to leave a comment but just tells me that I'm already logged in when I click on it, and I cannot find any...

A big thnx to everyone for your help on this problem. As all of you took the time to help out, I thought to share my final solution. Shout out to kuruman for the insight article; it was the crow bar I needed to pry out an answer. given: ##\Delta y## = 25.0 m, ##\Delta x## = 60.0 m, ##m## = 15.0...

I have attempted the problem a few times, and have posted my work below. I thought to check my work using ## v_x t = v_1 \times \cos\theta \times t = \Delta x## to see if I get back expected results, and I did for the horizontal motion (the substitutions are from the numbered steps below): ##...

Thnx so much for the response TNsy. Pointing out my contradiction between lines (1) and (2) was the big aha moment for me, and including the ##\rho gH## term makes the physical sense clear now.

Advanced apologies for this format; I am posting my question as an the image b/c the Latex is being very buggy with me, and I lost a kind of lengthy post to it. Can anyone show me what I am doing wrong? I have attached a pdf version for easier reading if need be.

I couldn't resist the parting comment that your original question brings to my mind, what are called in physics, the equations of continuity; they arose originally in fluid mechanics but the concept shows itself in electrodynamics and energy as well. I lifted a paragraph from a Wikipedia...

Thnx Charles. I am confident of my own answer then.

Homework Statement given: A wire loop with a circumference of L has a bead that moves freely around it. The momentum state function for the bead is ## \psi(x) = \sqrt{\frac{2}{L}} \sin \left (\frac{4\pi}{L}x \right ) ## find: The probability of finding the bead between ## \textstyle...

Sorry for delayed response; thnx are in order; I was away on vacation. Thank you Dick and Ray. The posts got me back on top of the curve (my Fourier forays are ten years ago now), so I committed them to my notes. I might be back for more regarding the M. Chester text I am reading. Thnx again.

Thnx much for that Dick! That was the fix I needed. Now it brings to my mind a question about the form of the exponential argument. The author wrote $$ C_k = \frac{1}{L} \int_0^L e^{-ikx} f(x) dx $$ and I used the form literally, but now I am concerned that I missed a basic Fourier series...

Homework Statement I am self studying an introductory quantum physics text by Marvin Chester Primer of Quantum Mechanics. I am stumped at a problem (1.10) on page 11. We are given f(x) = \sqrt{ \frac{8}{3L} } cos^2 \left ( \frac {\pi}{L} x \right ) and asked to find its Fourier...

Got it LCK, thnx!

Yes, I did get the sinking feeling I was begging the question after I posted So how about this? given:\hspace{10mm}\cos^{-1}(-x) = \alpha and \cos^{-1}(x) = \beta show:\hspace{10mm}\alpha = \pi - \beta from given \cos\alpha = -x \cos\beta = x\hspace{5mm} so \cos\alpha = -cos\beta \cos\alpha...