1. Homework Statement [/b]
Problem - Compute the potential difference between the points (4,6,3) and (8,1,6) due to a constant electrostatic field given by E = (2 ihat + 7 jhat + 12 khat) N/C. distance in metersHomework Equations
Fq = qE
Vr = Keq1/(r-r1)
Fq = (Kq1 (r-r1))/(r-r1)3
The...
Thanks so much, my last question is does it make sense that the same disposition of 13.05 cm when it is strectched and remains at static equilibrium would then also apply to when the spring is compressed and remains at static equlibrium. I believe the equation then should look like...
My work is as follows
(m*g*sinθ)+(Kx)=(μs*m*g*cosθ)
10.055+50x=16.58
50x=6.525
x=13.05 cm
I set the force of gravity and the force of the spring in the same downward direction bc when the spring becomes stretched upwards it wants to return to equilibrium, which is downwards, and...
A mass (m = 3 kg) is connected to a spring of constant k (k = 50 N/m), where the mass is connected at the top to a spring on a fixed incline. The coefficient of static friction between the mass and the incline is µ(subscript s) = 0.6 and the angle that the incline makes with the horizontal is...