Recent content by Grybas

1. 500 eV 2. v= √(1.6x10^-16 / 9.1x10^-31) v=1.33x10^7 m/s 3. p=mv p= (9.1x10^-31)x(1.33x10^7) p=1.21x10^-23 Kg-m/s 4. λ=h/p λ= (6.6x10^-34)/(1.21x10^-23) λ=5.45x10^-11 m Thanks a lot for the help! :)

2. v= √(1.6x10^-16 / 9.1x10^-31) v=1.33x10^7 3. p=mv p= (9.1x10^-31)x(1.33x10^7) p=1.21x10^-23 4. λ=h/p λ= (6.6x10^-34)/(1.21x10^-23) λ=5.45x10^-11 look ok?

2. V = KE / (1/2 * M) V = (8x10^-17) / (9.1x10^-31 /2) V = 1.76x10^14 is that right?

ok, i got that its 500 eV, now the velocity bit, not sure what formula to apply.

I'm struggling at these questions, i tried working out kinetic energy but i need velocity, but in the question it doesn't tell me anything about the speed the electrons are traveling at.

Homework Statement Some electrons are accelerated through a P.d. of 500 V. [e = 1.6x10^-19 C, mass of electron = 9.1x10^-31 Kg, h = 6.6x10^-34 Js.] 1. What is the kinetic energy of one of the electrons in eV? 2. What is the velocity of one of the electrons? 3. What is the...