Recent content by hanburger

Find the period T of the space shuttle Homework Statement (See image of problem statement for nice layout; the questions are stated below) A space shuttle of mass m is in a circular orbit of radius r around a planet of mass M in an alternate universe. In this alternate universe the laws...

Actually, I think I am wrong about the moment of inertia. I think it is also (8/3)md2 after the collision. So conservation of energy after collision gives 0.5Iω2 = mg(h-d) In this case, the moment of inertia is (8/3)md2. We then have d + (4/3)d2ω2/g= h Plugging in ω = (3v/8d), we have d +...

Okay, I think I've got it. The rotational inertia at the moment of collision is the inertia about the center of mass plus m*(sqrt(2)d)2 --> (2/3)md2 + m*(sqrt(2)d)2 = (8/3)md2 So conservation of angular momentum for before/during collision gives mvd=(8/3)md2ω --> ω = (3v/8d) Conservation of...

Oh. I didn't realize that. Okay, I'm going to attempt again. Lots of things to keep in mind in these problems!

Before the collision, angular momentum is mvd. When the collision happens, angular momentum is Iω. And after the collision, rotational energy gets transferred into gravitational potential energy 0.5Iω2 = mg(h-d)? So angular momentum is conserved before and during collision --> mvd=Iω And energy...

Thank you for your tips! I'm trying to apply them, as follows. Okay so the square is moving with angular momentum mvd. I'm confused as to the time frame. Because right when it hits the obstacle, it stops. So I would say that right when it hits the obstacle, its angular momentum is still mvd...

Oh yes! Parallel axis theorem. So Li = mvd. And Lf = (2/3*m*d2 + m*h2)ω0 v=ωr Would ω0 just be v/d?

Homework Statement A square shaped block of mass m travels to the right with velocity v on a frctionless surface. The block has side-length 2d. The block hits a very small, immovable obstacle on the floor and starts to tip. The block has moment of inertia Icm=2/3md^2 about an axis through...