haruspex's latest activity
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haruspex replied to the thread Motion in 2 dimensions.It's not based on a solution, merely the fact that an explicit equation like ##\dot\omega=\sqrt{b^2-\omega^4}## (positive square root... -
haruspex replied to the thread Motion in 2 dimensions.Ok, I do see now how multiple solutions arise. At any instant, we have ##\dot\omega^2=b^2-\omega^4##, giving two solutions for...
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haruspex replied to the thread Collision of a bullet on a rod-string system: query.Angular momentum of a body relative to a reference point has, in principle, two components: the spin angular momentum (its angular...
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haruspex replied to the thread Collision of a bullet on a rod-string system: query.Yes, the point of attachment moves, but my reference point doesn't. Let’s say there is a mark on the table at P. That is my reference...
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haruspex replied to the thread Collision of a bullet on a rod-string system: query.I'll say it again: my reference point for the angular momentum calculation is fixed. It is the point in space where the attachment...
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haruspex replied to the thread Motion in 2 dimensions.I suggest using the subjunctive here.
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haruspex replied to the thread Collision of a bullet on a rod-string system: query.Ha! Found my error. Missed two terms… Let the post-impact angular velocity be ##\omega## anticlockwise and the speed of the left end...
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haruspex replied to the thread Collision of a bullet on a rod-string system: query.Would you be happy to post your working, in a PM maybe?
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haruspex replied to the thread Motion in 2 dimensions.Involves ##\Gamma(1/4)##, right?
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haruspex replied to the thread Collision of a bullet on a rod-string system: query.No, I don’t fix that point. I wrote: I then expressed the motions of the rod and bullet in terms of these: That is, in the lab frame...
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haruspex replied to the thread Collision of a bullet on a rod-string system: query.See post #25.
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haruspex replied to the thread Collision of a bullet on a rod-string system: query.After the impulse, the string ensures that the left end of the rod stays at constant distance from the string's fixed point. This means...
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haruspex replied to the thread Collision of a bullet on a rod-string system: query.Quite so. Not so. Since the left end of the rod will have a speed, it is then describing an arc around the fixed point of the string...
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haruspex replied to the thread Collision of a bullet on a rod-string system: query.@Charles Link I think we are reading the question differently. It asks for the tension after the impact, not the tensional momentum...
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haruspex replied to the thread Angular Momentum- Conserved or not?.OP stands (at PhysicsForums) for either Original Post (but I prefer "post #1”) or Original Poster. In post #1, the OP wrote: "i) I do...