Recent content by hayu601
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Matrix transformation and inequality
A < B means that (B-A) > 0 or (B-A) is positive definite- hayu601
- Post #3
- Forum: Calculus and Beyond Homework Help
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Matrix transformation and inequality
Homework Statement Suppose U and V are unitary matrix, A and B are positive definite, Does: UAU-1 < VBV-1 implies A < B and vice versa?- hayu601
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- Inequality Matrix Transformation
- Replies: 3
- Forum: Calculus and Beyond Homework Help
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Proving σmax(A-B) ≤ σmax(A) - σmin(B)
Is it true if I state: σmax(A-B) <= σmax(A) - σmin(B) ? I verify numerically that it is correct but how to prove it?- hayu601
- Thread
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Graduate Matrix Inequality: Is BTB <= B1TB1?
I am puzzled about this simple case, Suppose we have (A+B)T(A+B) <= (A+B1)T(A+B1), Can we say something about the relation between BTB and B1TB1? For example, is it correct if I say BTB <= B1TB1?- hayu601
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- Inequality Matrix
- Replies: 1
- Forum: Linear and Abstract Algebra
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Independent Subspace: Proving (or Disproving) Linear Independence
It means that every bi element B is not linear combination of vectors in D- hayu601
- Post #3
- Forum: Calculus and Beyond Homework Help
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Independent Subspace: Proving (or Disproving) Linear Independence
Suppose B = {b1,...,bn} and C={c1,...,cn} both are basis set for space V. D = {d1,...,dn} is basis for space T. If B and D is linearly independent, is C and D always independent too? How can we prove (disprove) it?- hayu601
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- Independent Subspace
- Replies: 3
- Forum: Calculus and Beyond Homework Help