Recent content by hdr

Thanks for the reply. Here is what I did: 600MW*365*24*3600 = 18.9216*10^12 kJ/year 18.9216*10^12 kJ/year *(capacity factor "0.85") = 16.0834*10^12 kJ/year <==actual output Amount of coal = (16.0834 *10^12 kJ/year)/22800 kJ/kg = 7.0541*10^8 kg/year (coal) Boiler's efficiency=88% => (7.0541*10^8...

I absolutely read the question (I didn't post the last reply). I calculated the annual power generated in power plant. Is the mass of sulfur going to be 0.46% of the mass of the coal because it says "and contains 0.46 wt% sulfur" ? Thank you

Homework Statement A coal-fired steam power plant operates on the ideal Rankine cycle. Feedwater from the condenser at P1= 10 kPa is pumped to the boiler at P2= P3 = 20 MPa, where it is superheated and exits the boiler at T3 = 550 °C. The moisture content in the turbine is not to exceed 12%...

Homework Statement A coal-fired steam power plant operates on the ideal Rankine cycle. Feedwater from the condenser at P1 = 10 kPa is pumped to the boiler at P2 = P3 = 20 MPa, where it is superheated and exits the boiler at T3 = 550 °C. The moisture content in the turbine is...