How did you find (B) and (C) and also spring at equilibrium point, isn't that when the spring neither is stretched or squeesed (x=0), but how did you get -0.0015m in B?
So you think if the velocity should add up to be 8,73m/s as if the bike was stationary relative to the earth, the velocity relative to you and the bike should be 8,73=(20km/h)/3.6 * v(youandbike), and solve for v(youandbike) = 3.17m/s ?
Yes, but then the right sides will be: tan(θ) / l) i the first eq. and in the second: (tan(θ) + h ) / d, and when you put these two equal to one another the tan will go away?
So how did you then get θ=tan^-1(lh/d(d-l)) ?
Well, that's explanes why i got wrong, i searched for the radius and mass of Earth on google, didnt se that they were mentioned in the task :) Now i should get the right answear..
Yes, might be that that is wrong then? But you said that (G*M*m)/r^2 is the force and since F=m*a where a=v^2/r you can solve the problem by solving it for v and then setting in the formula for T instead. Can i not use that (G*M*m)/r^2 = m* v^2/r, and solv it for v, then put v in T = 2*pi*r/v ?
Did you get the periode for the object to do one lap equal to 268,7s ?? Felt that this answear was very small, but i got the formula T = 2*pi*r / (sqrt(G*M/r)