Recent content by hehehe

thank you, you are a patient and good teacher. you have a full explanation ,thank you again.

##\lim_{x\rightarrow -1}|x+b-2| = |b-3|## but i don't know that value of b when a=0 ,how can i compute. similarly,when b=3, ##\lim_{x\rightarrow -1}(ax+|x+1|) = -a## ,it is same with the above one when a=0 ,b=3 ,##\displaystyle \lim_{x\rightarrow -1} f(x) = 0 ##

##|x+b-2|## for ##x \neq -1## , i don't know what is your meaning if i just substitute -1 to the limit , then i get lim ##x \to-1## ##|x+b-2|## the next step is that do it in left-hand limits and right-hand limits? but i don't not have to distinguish |x+b-2|?

at x=-1 (ax+ (x+1)) |x+b-2| =0 -a|b-3| =0 a=0 , b=3 but i have a problem , can |b-3| = b-3? i put a=0 and b=3 to the lim and do it in left-hand limits and right-hand limits left-hand limits=right-hand limits=0 ,so it exists is it right? Samy_A thank you

(ax+ (x+1)) |x+b-2| =0 for x≥-1 (ax+ (x+1))=0 a=-(x+1)/x or |x+b-2| =0 b=2-x (ax-(x+1)) |x+b-2| =0 for x<-1 a=(x+1)/x or |x+b-2| =0 b=2-x (x+1)/x =-(x+1)/x x=-1 b=2-(-1)=3 a=-1 and b=3 when limit will exist is it right ...

Homework Statement http://holland.pk/nwhxy2ji 2. Homework Equations The Attempt at a Solution |x|= x for x≥ 0 and |x|= -x for x<0 |x+1|= x+1 for x≥ -1 and |x+1|= -(x+1) for x<-1 I don't know how to determine |x + b − 2| is positive or negative. i know that if limit exists, lim x→ −1 ^- f(x)...

what value of the constants a and b if the following limit exists lim (ax + |x + 1|)|x + b − 2| |x + 1| x→−1 |x|= x for x≥ 0 and |x|= -x for x<0 |x+1|= x+1 for x≥ -1 and |x+1|= -(x+1) for x<-1 I don't know how to determine |x + b − 2| is positive or negative. i know that if limit...