Recent content by helgamauer

* And i meant (2^m -1) and (2^n -1) are two different ODD primes. May anybody help?

We have: z = (2^(mn) - 1)/[(2^m - 1)(2^n - 1)], where (2^m - 1) and (2^n - 1) are prime numbers. Prove that (2^m - 1) and (2^n - 1) are not the only prime factors of z. I tried to solve it writing z = (2^m - 1)^a * (2^n - 1)^b and proving that it is not correct. But I don't know how. I also...

Prove, that if (m,n) = 1 // m and n are two different primes then (2m -1, 2mn -1/2m -1) = 1

And one more.. Is from #1 easily derivable that If (m,n) = 1 then (2^m - 1 , 2^n - 1) = 1 ?

Well... You are great! Thank you so much. I don't want to be importunate, but do you have any ideas how can I solve two remaining problems? 2.Prove that a composite Mersenne number ((2^d - 1) is composite, d is prime) has at least 2 prime divisors. 3.Is it possible that (2^t - 1)^a * (2^u -...

Then could you please write it more simply? Please, it is very important for me.

Oh.. Would it be possible for you to write it in latex or annex a photo of those equations? I can't fully understand it this way.. Please, I would really appreciate.

Hello. I've got three questions. 1.Can a Mersenne number be a multiple of another Mersenne number? Prove. (I mean is that possible that 2^a - 1 | 2^b - 1 where a, b are prime numbers) 2.Can a Mersenne number be equal to X^n ? (X and n are integer). Prove. (This Mersenne number is 2^d - 1 where...