Recent content by hello12345

if you are referring to this question, think really hard back to indices laws x^2*x^3=x^5 ( when you multiply you add ) (e^x)^2 =(e^x)(e^x)=(e^2x) Anti D = (1/k)*(e^2x)+c ( note 2 is K ) (1/2)*(e^2x)+c