Recent content by helmi

that makes perfect sense, thanks cepheid :smile:

If the Earth rotates 1670km/hr why can't I just hover high enough (assuming there's enough fuel) and wait for my destination to arrive? Haha

ok i went ahead & solve the equation to get x=0.522...but when i substitute x=0.522 into the initial equation i did not get 2...what hv i done wrong?

ok I've done the 1st step by changing log2 2x to (log3 2x)/(log3 2) (log3 2x)/(log3 2) - log3 (3x-1) = 2 1.585(log3 2x) -log3 (3x-1) = 2 log3 (2x)^1.585 - log3 (3x-1) = 2 log3 ( (2x^1.585)/(3x-1) ) = 2 , is this correct? then what?

log2 2x -log3 (3x-1) = 2, solve for x... you guys don't hv 2 solve the question for me, just guide me to the answer:smile: