Recent content by helpinghand

All good. I will need to apply this to what I am currently doing and double check if it will be a problem. really appreciate all the help and assistance.

It is the amount the springs are going to be compressed by. I.e the spring displacement.

Hi guys, Cheers for all the help. The data provided was just put together. The main information is trying to determine the new pocket depth required for the shorter spring. 1. I have a long spring in a pocket with a fixed depth. 2. I have a shorter spring, but need to determine the new pocket...

This part I understand. But how does it affect the depth of the pocket retaining the new spring, would it mean I would need a new pocket depth of 14mm to get the same effect?

Yes, based on the data provided - N/m

The original spring compresses by 9mm

Hi Guys, Forgive me, as it has been quite sometime since I have done my spring theory. The problem I am having is the following: This is the current situation: - In a steel block I have a pocket depth of 15mm - I have a compression spring with the following information: Outside diameter is...

Thanks heaps Studiot for all the help :D

R_B = P(a+ \frac{3}{2} (L-a)) So then this goes into the equation to find δ at C

ok, so then deflection at C is: ~ in which I get \delta = \frac{{{-R_B}{a^2}(3L - a)}}{{6EI}} + \frac{{P{L^3}}}{{3EI}} The only part at the moment is still can't quite see how you would still find RB. So are you saying that there should be another part which goes into the equation...

I'm still a little lost on how this would help me find the reaction at B... So, which slope equation should I be using?, because I am just getting confused. And do I need the deflection equation with the slope equation to find the reaction at B? yep, so just like what I said earlier...

So are you talking about the beam from the fixed end (point A) to point B? Do you mean like the deflection and slope at B would be zero?

ahh... bugger, I must of forgot moment at A, sorry. so it should be ƩMat A=0=M-P2L+RBL → RB=(M+2PL)/L Does it mean that if I was to take the moment around point B, it would be ƩMat B=0=-PL+RAL → RA=P ??

Just another thought, is it possible to use superposition principle: Case 1:Find the deflection between point A and C without the support of point B Case 2:Then find the deflection between A and B (i.e. delfection going upwards) The total deflection is equal to case 1 + case 2 But this still...

ƩMat A=0=-P2L+RBL → RB=2P I just used the summation of moment at point A to find the reaction a point B which was then related to finding the deflection of the beam. Isn't the slope-deflection equation just θ=...? , but I don't see how that helps me find the deflection at the end of the beam.