Recent content by Hendrik

Hi Benorin, Hi Hurkyl, meanwhile I solved the problem using mathematica instead of maple which I found out is much more performant numerically. I still don't know if it works other way, but thank you guys, anyway. Hendrik

Thanks for the answer, but no, I meant: \psi_n(z) = \int_0^{2\pi}\int_0^1 \frac{ (z-\frac{1}{2}) \cdot (r \cos(\theta) + \frac{1}{2})^n \cdot r} {\sqrt{4z^2+4r^2+4r\cos(\theta)+2-4z}^{2n+3}}\,dr\,d\theta ...sorry for the latex trouble. Taking out the constants is a good idea and it might...

Hi, I am new here, but apparently there are some decent mathematicians around, so I would like to confront you with a double integral problem. Consider \psi_n(z) = \int_0^{2\pi}\int_0^1 \frac{ (z-\frac{1}{2}) \cdot (r \cos(\theta) + \frac{1}{2})^n \cdot r}...

Hi, I am new here, but apparently there are some decent mathematicians around, so I would like to confront you with a double integral problem. Consider \psi_n(z) = \int_0^{2\pi}\int_0^1 \frac{ (z-\frac{1}{2}) \cdot (r \cos(\theta) + \frac{1}{2})^n \cdot r}...

Hi, I am new here, but apparently there are some decent mathematicians around, so I would like to confront you with a double integral problem. Consider \psi_n(z) = \int_0^{2\pi}\int_0^1 \frac{ (z-\frac{1}{2}) \cdot (r \cos(\theta) + \frac{1}{2})^n \cdot r}...

Hi, I am new here, but apparently there are some decent mathematicians around, so I would like to confront you with a double integral problem. Consider \psi_n(z) = \int_0^{2\pi}\int_0^1 \frac{ (z-\frac{1}{2}) \cdot (r \cos(\theta) + \frac{1}{2})^n \cdot r} { \sqrt{...