I want to thank everyone for their help with this problem. I finally got the right answer.
Looking at this problem now with a clearer mind, it is not that it is difficult, it just requires a review in angles and trigonometric formulas.
I am in the calculus based course, but since we just...
After doing all of this before, I felt as though I was going in the wrong direction.
I have two forces acting on Q3: Force of Q1 on Q3 and Force of Q2 on Q3.
I know I need the tangential component which has always been easy to derive by multiply the force by some cos(angle). However, this...
My latest attempt at solving this problem was to find the value on an x-axis where the charge would feel no net force. I did this by setting (K*Q1*Q3)/(2R-x)^2=(K*Q2*Q3)/(x^2) and I got .148 meters. I then used the conversion to polar coordinates R*cos(theta)=x and I got 45.8 degrees. This is...
I apologize for that, I forgot that my computer kept me logged in. Here is a new link:
http://i783.photobucket.com/albums/yy117/chershey7/semicircle.gif
Essentially, it is two point charges on an x-axis separated by a distance of 2R. A third point charge Q3 is located on a semicircular arc...
Homework Statement
Two point charges Q1 = 69.5 μC and Q2 = 19.9 μC are fixed on the two ends of the diameter of a semi-circle with a radius of r = 21.3 cm as shown in the figure...