for the 24kg i did T-Fwsin20=24a, for the 11 kg Fwsin20-T=11a, then i added them together to get the equation, 107.8sin20-235.2sin20=35a. Then i got -1.245 for a. Then i attempted to plug a into each of the original equations to solve for T, but got two different values (the correct answer is...
since the blocks are moving together, the acceleration is the same for each block...so it's only necessary to solve for acceleration in one of the blocks, in this case the 3kg block since we don't know the tension force
never mind...i got the answer by adding up the two net equations for each block and then solving for a. I then plugged that answer into the net force equation for one block to find T..but what's weird is that i got a different answer for T when i plugged it into the 11kg block (the wrong answer)...
ok, i did that and webassign marked the answer wrong. I followed rl.bhat's help by setting the two equations equal to each other because the accelerations are equal, and i solved for T. Then i plugged that into find a, but i found that the a's in the two different equations were different. Is...
ok..so i tried doing that and solving for T, but the website (webassign) still marks it wrong. Also, the 24kg block is on top of the 11kg, so wouldn't the acceleration of the upper block be [T-24gsin20]/24 ?? Doing it this way, i got 89.26N as T. I also tried it your way and it marked it wrong.
ok..so how would you start then? I tried it by using F=ma using the system, so i used the total mass and the net force( which is i think 117.31 using both the Fw parallels to the plane for each block). I thinkit may ybe different because its two masses on top of each other..not one hanging
Homework Statement
This is a problem with two masses, a 24kg block sliding on an 11kg block. All surfaces are frictionless. Find the magnitude and acceleration of each block and the tension in the string that connects the blocks. The incline is 20 degrees. * this is not an atwoods...