I am given 2 mass spectra of protein fragments and don't get how to analysis a mass spectrum of a protein and find Z value with the given m/z ratios.
do i take the mass of the whole protein and divide by the m/z on the spectrum to find z?
thanks
I used NCBI Blast and Ensembl.
Blast results gave Mad3/Bub1 domains when searched.. but i don't think those are orthologs? they are just a domain that san-1 has??
and ensembl didn't find any.
because I'm trying to find orthologs on this gene called san-1 from C. elegans, But it doesn't seem to have any. So my assignment saids to try finding it with its novel gene.
So novel gene is not really a gene? I'm confused. does it have a name though?
I mean the values 186.19 J/K/mol and 229.49 J/K/mol for methane and ethane given in the question. If i use the equation i said above, then these values would not be needed; so I was thinking there might be another way to do this...
"Note that the term represents an additional term to augment...
Homework Statement
at 25C & 1 atm, absolute entropy of methane and ethane are 186.19 J/K/mol and 229.49 J/K/mol in gas phase. Find absolute 3rd law entropy of a solution containing 1 mol of each gas in ideal behavior.
Homework Equations
I think this is the equation to use:
dSmix=...
if its not a state variable (i.e heat (q)), it would be path dependant, which means for a complete cycle, you would have to add up the heat at each step, correct?
ya, enthalpy is a state variable. so this means that it doesn't depend on the path, right? so if i want to find change in enthalpy, it will be the final enthalpy minus initial enthalpy?
if I want to find the enthalpy change of a whole cycle, do i add up all the enthalpy of each step? The system goes from A to B, from B to C, and from C back to A
dH = dU + P dV
dU = q - P dV
I need to find the dH for a system (1mol gas)going from P=1.24 atm to P=0.62atm, with constant volume of 46.72 L. I already found the value of q = -4402 J, w=0 , and dU = -4402 J
I think dH = dU since its change in V is 0. So my answer was dH =dU = -4402J...