Recent content by homeworkboy

i found the time using t = 2Voy/g which came out to be 4.2 seconds...and then wat do i do??

i got another one A baseball is hit with a speed of 27.0 m/s at an angle of 49.0 degrees. It lands on the flat roof of a 14.0 m tall nearby building.If the ball was hit when it was 1.4 m above the ground, what horizontal distance does it travel before it lands on the building?

Oh ok...i thought that trigonometry of vectors only applies when we are dealing with velocity..sorry..thanks i got the sum...i then used the second eq of motion... X=volt + 1/2at2

I don't even understand how it should be approached

A skier is accelerating down a 30.0 degree hill at 1.80 m/s2. What is the vertical component of her acceleration? How long will it take her to reach the bottom of the hill, assuming she starts from rest and accelerates uniformly, if the elevation change is 375 m

i don't know wat formula ur tokin abt

no they will not have identical velocities. so yea they will be the same distance between them. I don't know 2,

1. Two identical balls are dropped from rest, one at t=0, and the other a second later. Does the distance between them increase, decrease or remain the same.? Explain. 2. Write the general equations, in one dimension, for position and velocity of an object which experiences a constant...

bump...anyone

I dint understand your explanation...is there anyone else who can help me..

well since it says it tokk .14 sec to travel 2.2 m then velocity (v) = 2.2/.14 then we get the final velocity...we know a = -9.8 m/s2...and X = 2.2+9 =11.2m...so we find initial velocity but it says that its the wrong answer so if u teach me the method it would be great...

bump please help

A toy rocket moving vertically upward passes by a 2.2 m high window whose sill is 9.0 m above the ground. The rocket takes 0.14 m/s} to travel the 2.2 m height of the window. What was the launch speed of the rocket? Assume the propellant is burned very quickly at blastoff. How high will...

Hey thanks a million! i perfectly understood it...i worked it out the way u said and it came upto 2.86 (since i used 9.8m/s2)...so i checked it and it was the right answer..thanks a lot..

bump please help