Recent content by houseonfire

(a)If there is no air, the pressure inside the syringe is just zero, therefore I would need to pull the plunger down with a force equal to the (atmospheric pressure * cross sectional area of the syringe) (b)When there is a large volume of air, experience tells me that the plunger moves down...

Thanks jbriggs444 for your reply. I think it is: [(Atmospheric Pressure) minus (Pressure inside syringe)] times [cross sectional area of the syringe)] I wanted to understand why less force is required when pulling down the plunger if the initial volume of air inside the syringe is greater...

Hi berkeman Thanks for your reply. Ok, not sure if this is right but... pV = NkT ⇒ p = NkT/V assuming NkT is constant, ⇒ δp = NkT ln(V)δV (where N is the total number of particles and k is Boltzmann's constant) ⇒ δV ∝ δp / Nln(V) Is this right? so if we pull down the plunger with a...

Hello I had a question, related to a recent experiment we've done, that I have been thinking about for a while now. Hopefully someone can help as it has been bugging me! Consider two situations: A: a syringe is filled with 5ml of air and then sealed B: the same syringe but now filled with...