Recent content by htetaung

if we have to set things up so that they never meet again then it is not a full theory - there are limitations. In twins paradox the one who speeds up finally turn back and the twins meet again.

this clearly is not an answer.

Thanks for the reply. But in my opinion, there is one weak point - you are using only one frame that does the observing. I know twin paradox by the way. To make it scientifically precise, let's say A, B, C, and D have synchronized clocks. More importantly, say there is nothing to regard as...

hi there I am confused by the following setting on special relativity: Suppose there are 4 people, say A, B, C and D, in the deepest vacuum - essentially no gravity or any force at all. Suppose further that all move in one-dimension with constant velocities - A moves towards west with 0.8c...

Thank you. I think I got it.

Thanks for your reply. But I don't know about topology. So is there anyway to understand its infinitely long geodesics? Why are those things infinitely long?

hi there What is a Poincare' disc and why is the edges of disc represent infinity? thanks

I am really sorry, I did a big mistake. I assumed the mass to be constant. Mine is flawed

hi there I have a solution for your problem but I am not sure it is right. Anyway, here it is. I started with the relation W = (integral)F dx Work done equals change in kinetic energy and initial KE is zero. Plugging in W = 0.5mv(squared) and F = (x/L)mg and integrating it, I got Lv(squared)...

hi there again, T - f = Ma*a __________ 1 Mb*g - T = Mb*a ______ 2 Add 1 and 2, you get: Mb*g - f = (Ma + Mb)a Plug in everything except a, and you get exactly 4.775 Plug in the value of a in any of the two eq's.

I got them by separately using Newton's second law for each block. net force = mass times acceleration

hi there In the first eq, you know friction and mass of A. For the second eq, you know mass of B and g. This gives you a two simultaneous eq's in two unknowns which I think is easy enough to solve. You have two eq's, not one.

hi there Your question gives inadequate information, whether blocks are on a table or not. But from the available data, it is reasonable to assume that block A is on a table, block B is hanging around the pulley - those are my assumptions. Under my assumptions, look at the block A first...

hi everyone, the problem is a simple one as danishtanwar said. Though I have an explanation, I am not quite sure if it is right because I created it myself. And the action-reaction law seems to invalidate my result. Here is my calculation. First, Newton's second law for the whole system...

Hi there! The force that govern what you are saying is called precession. Precession can be seen when you ride a bicycle. It is this precession force that keeps you standing on 2 wheels. I don't know much about the principle of precession. But precession is the main character in a gyroscope...