Ok, excellent. So... would this be right?
KEtot = KEr + KEt
(Mw*Vw^2)/2 = (Mr*R^2*(2*pi*ƒ)^2)/2 + (Mo*Vo^2)/2
where
Mw = mass + extra weight (fixed)
Mo = mass (without extra weight fixed)
Mr = mass of extra weight (which will rotate)
ƒ = revs per second
and assuming the extra weight is a...
I think you're saying that it takes more energy to move a point on the wheel because the engine must accelerate it angularly and translationally. So, regardless of the weight distribution of the disk, it will always take more energy to move rotating weight than non-rotating weight (in this...
Lets say the disk (rear wheel) is solid and of uniform density. Let's also assume that the weight savings of the disk is made by decreasing the density of the disk. So that the dimensions are constant but it weighs less, e.g. Mdisk > (Mlightdisk = Md/4).
I've looked at the equations for torque, inertia, and angular acceleration, but I still can't figure this out. I was hoping someone could push me in the right direction.
This is the question I'm trying to solve:
In a situation where an engine propels a required amount of weight, is a...