Okay, I think I understand it now (hopefully!)
So, 11,46m3 is equivalent to 11460kg. Then, to find the Weight of that, I'd times it by 9.8, giving me 112308N. Then, i'd just divide that by 686?
Right... So I'm guessing that you would need to find how many people can be added into the crate? Like, for 1 person, it would be 19*(10070/10250)? =Ans. Then, Ans/15? Then, just continue going until that value goes to 0 or less?
Well, I assuming that all you do for that is 18.54m3/15m2=1.236m. So, it has sunk 1.236 metres, meaning that 0.764 metres of the crate isn't submerged?
Okay, I think I get that part... So, because the bouyancy force is equal to the weight of the fluid, I'd use
Fb=gpV, which is 9.8*1.025(Salt water)*30=301.25, which means that the weight of the displaced liquid is 301.25N? Continuing from that, does that make the volume of the water 301.25L?
Archemides Principle states that the upward bouyancy force is exerted on a body immersed in liquid, is equal to the weight of the fluid that the body displaces.
So, does that mean I need to calculate the weight of the displaces liquid? Do I use the equation:
V= (Normal Weight in air - Weight...
As I've said, my class hasn't been taught how to do bouyancy questions yet. I looked over my Notebook incase I completely forgot about doing it, but there is absoltuely nothing when it comes to bouyancy. When I searched up the Principal on the Internet, it looked to me as if it can only be used...
Homework Statement
A large number of people are on a sinking ship, and decide to use a large crate with an open top as a lifeboat.
A physicist in the crowd has been tasked with finding how many people can board the craft before it would sink. She assumes the average person has a mass of 70kg...
For me, up is positive, and down is negative. Also, I wasn't aware that g was involved for that equation, aside from being used for the acceleration. Have I made a stupid mistake?
Okay, thanks for the reply! Here's what I've done:
I rearranged s=ut+0.5at^2, so that I could find u. ( u= (s-0.5at^2)/t)
So, when I substitute in the values, I get:
u=(2-0.5x-9.8x0.6^2)/0.6, which gave me an answer of 6.27m/s.
I'm not too confident on whether this is correct or not though.
Hey guys, I'm wondering if I can get some help with a question in my homework. Here's the question:
A workman on the scaffolding outside one of the physics classrooms drops a wrench. A pupil decides to time how long it takes for it to pass the classroom window. It was found that it took...