Recent content by I2use

Thank you, both of you, that link was very appropriate! I got this far: Let it fall from mount Everest and the velocity will be 384.7m/s when it hits the ground. F=ma and a=finalvelocity-startingvelocity/time which would be 0-384.7/the time it takes for the ball to travel 10m which would be...

The fulcrum is the centre - 5m high (I was trying to describe it but did not know the correct word). I would like to change the mass of the object instead of the fulcrum position. Also what is the equation for how fast an object approaches its terminal velocity?

This is not homework, it is purely for my own enjoyment. Say I have a lead sphere with a one meter radius, a mass of 465800N and a terminal velocity of 1290m/s. Say I also have a different spherical body of 685N. I now place the 685N body on one side of a seesaw of 20m in length and a height...