Recent content by i4k20c

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    Finding RLC from Freq and Impediance (AC Ckt)

    hmmm. okay, from that i get something like this. \omegaL=1/\omegaL => \omega=1/\sqrt{LC} = 60/2(pi) so LC=(2pi/60)^2 and rewriting it in terms of L=(2pi/60)^2 * (1/C We also know that \vartheta=(tan^-1) [2(pi)(50)]-([1/(2(pi)(50))]C)/R so plugging in our unknowns i should get...
  2. I

    Finding RLC from Freq and Impediance (AC Ckt)

    sorry for the multitude of questions, i want to say i truly appreciate your help. the equation for resonant frequency is fr=\omega/2(Pi) and the equation for thetha==(tan^-1)[(Xl-Xc)/R] so would i be plugging in 2.8=(tan^-1)[(Xl-Xc)/5000ohms]? and i know that Xl=\omegaL and...
  3. I

    Finding RLC from Freq and Impediance (AC Ckt)

    \theta=(tan^-1)[(Xl-Xc)/R] however using what you said in the post below, if Xl and Xc are equal at resonance than it would equal 0, and 0/Resoancne * tan-1 would equal 0; however it is not, the angle is 2.8 as stated by the problem... which is where i get confused! :confused:
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    Finding RLC from Freq and Impediance (AC Ckt)

    after speaking with a friend, i realize that at resonance the impedance is the resistance, so R=5000ohms, but that still doesn't give me much in solving for L or C...
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    Finding RLC from Freq and Impediance (AC Ckt)

    [SOLVED] Finding RLC from Freq and Impediance (AC Ckt) Homework Statement 1. Determine the values of R, L and C in an AC circuit to satisfy the following criteria: (i) the impedance at resonance is 5 k Ohms (ii) the resonant frequency is 60 Hz (USA standard) (iii) the voltage lags the...
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