Recent content by iamzzz

I am going to read textbook. Did not attend class Thanks for the hlep

no The question did not give the formula of the transformation

C1*(1,1,-1)+c2(1,0,-1) C1=-5 and C2=5 -5(1,0,1)+5(1,7,-1)=(5,30,-5)

i don't knwo :(

T((1,1,-1)) and T((1,0,-1)) should produce something close.

Homework Statement You are given that T is a linear transformation from R^3 to P2, that T((1,1,-1)) =X, and that T((1,0,-1))=X^2+7X-1. Find T(0,-5,0) or explain why it cannot be determined form the given information. Homework Equations None The Attempt at a Solution There is only X...

Thanks I should add A0=B0

Thank you for all the help.

Thank you

Ax1=Bx1 =>mutiply x2 on both side=> Ax1*x2=Bx1*x2 => A(x1*x2)=B(x1*x2) is this enough to show close under sclar multiplication ?

Yes Ax1=Bx1 =>add Ax2 on both side=> Ax1+Ax2=Bx1+Bx2 => A(x1+x2)=B(x1+x2) is this enough to show close under addition?

a subset of a vector space that is closed under addition and scalar multiplication Let H be a homogeneous system of linear equations in x1, ...,xn . Then the subset S of R^n which consists of all solutions of the system H is a subspace of R^n .

I mean does that prove the problem ? Anyway thanks for the help

Homework Statement Let A be an n*n matrix and let B be a real number, Nothing which properties of matrix multiplication you use, show that the set W= {x member of R^n | Ax=Bx} is a subspace of R^n, where x in the equation Ax=bx is represented by a column vector instead of an n-tuple with...

let x1 be the solution of Ax1=b1 and x2 be the solution of Ax2=b2 So Ax1+Ax2=b1+b2=A(x1+x2) so (x1+x2)could be x prove ? Is this correct ?