I corrected the above equation as follows
s = ut + gt2/2
u = g (t0)
t = 4
so 196.2 = 9.81 * t0 * 4 + 9.81 * 4 * 4 / 2
t0 = 3
The marple fell 3 seconds to cross 44.15 m, then it traveled 4 seconds and covered 196.2 m
So the marple fell 240.35 m in 7 seconds.