Recent content by ido25

And , may i add, this was a part of a test... so unfortunatly i cannot change the question. i need to know if i can win this case with the current solution..

Ok, the equations were written in the test : 1/2 (0.5Kg) (V(0) ^ 2) = (0.5 kg) (9.8m/s^2) ((-0.1m)sin30) + 1/2(400N/m)(-0.1m)^2 i had to "invent" a problem, that should be solved with the exact same equations. the problem that i invented was described above.. unfortunatly, i choosed...

thanks Doc. actually the question was vice versa - it was just easier for me describing the problem like this in this forum. In the original question the equations were given, and i was asked to "write" a problem, that should be solved with the equations. the problem i invented was...

I was asked to solve the following problem: A box is sliding down a plain inclined 30 degrees above the horizontal. towards a spring attached to the start of the plain. when the box hit the spring its velocity is V(0). the box continue moving for another 0.1m until a complete stop. *...