Recent content by idontkonw
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Graduate A little problem with charge operator
Oh man, I'm feeling really really genius... I think it's time to stop studying. Enought for today. What a big mistake. All for no writing long expressions... Thanks a lot!- idontkonw
- Post #5
- Forum: High Energy, Nuclear, Particle Physics
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Graduate A little problem with charge operator
mmm let me explain how I'm doing this. Let's take the last way of 3.20: Q(|u\uparrow u\downarrow d\uparrow> -2|u\uparrow u\uparrow d\downarrow>)= \left[ \left(\frac{1}{2}\frac{1}{3} + \frac{1}{2}\right)+\left(\frac{1}{2}\frac{1}{3} + \frac{1}{2}\right)+\left(\frac{1}{2}\frac{1}{3} -...- idontkonw
- Post #3
- Forum: High Energy, Nuclear, Particle Physics
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Graduate A little problem with charge operator
I have a problem where it's said that the operator Q is likely to be: Q=\sum^3_{i=1}[\frac{1}{2}B_i + I_{3,i}] I have to apply this to the proton wave function which is the same as you can see in equation (3.20) here...- idontkonw
- Thread
- Charge Operator
- Replies: 4
- Forum: High Energy, Nuclear, Particle Physics