Recent content by IEVaibhov
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Undergrad Zigzagging Up an Incline: Does It Help or Hinder Cyclists?
@berkeman : I think that while going in a zigzag path, the frictional force acting on the tyres will be reduced. Suppose that the inclined plane makes an angle A with the horizontal, friction coefficient is u, and the cyclist is driving on a zigzag path. Consider a part of the zigzag path - if... -
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Undergrad Zigzagging Up an Incline: Does It Help or Hinder Cyclists?
Ok, that is interesting. How does low gearing help? -
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Graduate Energy possessed by Electric Field
Consider a parallel plate capacitor. It is said that electromagnetic waves store electrical energy. Since electromagnetic waves don't require a medium to propagate, we can say that electrical energy can be stored in a space where there are no medium particles (say vaccuum). Where exactly is...- IEVaibhov
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- Electric Electric field Energy Field
- Replies: 2
- Forum: Electromagnetism
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Undergrad Zigzagging Up an Incline: Does It Help or Hinder Cyclists?
Consider a cyclist going up an inclined plane. Will going in a zigzag path make it easier for the cyclist to go up the hill? (Assume that there IS friction on the incline) -
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Sum of n Terms of 7/(1.2.3) - 17/(2.3.4) + Series
Oh wait, I got the summation only for the numerator part.- IEVaibhov
- Post #11
- Forum: Precalculus Mathematics Homework Help
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Sum of n Terms of 7/(1.2.3) - 17/(2.3.4) + Series
To me, this looks like - Sn = a1 + 5*2 + 7*2 + ... (till n terms) and an = a1 + 2*(2n+1) ; n is a natural number that lies between 2 and n. So, Sn = [n(2a1 + 4n + 2)] / 2 (Since Sn = n(a1 + an) / 2 ) Therefore, Sn = n[16 + 4n] /2 = 8n + 2n^2 ( n going...- IEVaibhov
- Post #7
- Forum: Precalculus Mathematics Homework Help
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Magnetic force on a moving charge particle with friction force acting on it
I have solved the problem. I am just too lazy to type the WHOLE thing out here. The solution is kind of long. Basically, get the general velocity along X axis and Y axis as a function of time. To obtain this, in the penultimate step, you will get a differential equation that you will have to...- IEVaibhov
- Post #3
- Forum: Introductory Physics Homework Help
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Sum of n Terms of 7/(1.2.3) - 17/(2.3.4) + Series
We need a (-1)^n term in the general term for the sign change, that is okay.. Now, I know 2 things : 1: 17 = 7+10 2: 31 = 17 + 14 3: 14 = 10 + 4 Let me put the above two equations in variable form. Consider this - 7 = x1 17 = x2 31 = x3 10 = y1 14 = y2 and 4 = z1...- IEVaibhov
- Post #5
- Forum: Precalculus Mathematics Homework Help
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Sum of n Terms of 7/(1.2.3) - 17/(2.3.4) + Series
If you consider the difference between the difference of the consecutive terms, it comes out to be constant. 7 17 31 49 10 14 18 4 4 Now what?- IEVaibhov
- Post #3
- Forum: Precalculus Mathematics Homework Help
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Sum of n Terms of 7/(1.2.3) - 17/(2.3.4) + Series
Find the sum of n terms of the series: 7/(1.2.3) - 17/(2.3.4) + 31/(3.4.5) - 49/(4.5.6) + 71/(5.6.7) - ...I know how problems like the following are solved : 1. 1/(1.2.3) + 2/(2.3.4) + 3/(3.4.5) + ... 2. 3/(1.2.4) + 4/(2.3.5) + 5/(3.4.6) + ...What will be the general term of the required...- IEVaibhov
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- Series Summation
- Replies: 12
- Forum: Precalculus Mathematics Homework Help
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Plotting the graph of y=1/log|x|
I was just wondering as to how I can plot the graph of y=1/log|x| without putting a lot of values of x and obtaining corresponding values of y. I mean, how can I draw this graph using the graph of y=log x or the graph of log|x|? Is there a way?- IEVaibhov
- Thread
- Graph Plotting
- Replies: 2
- Forum: MATLAB, Maple, Mathematica, LaTeX
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Undergrad Is there a correlation between compressibility factor and temperature in gases?
Maybe, I haven't understood her doubt correctly. -
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Undergrad Is there a correlation between compressibility factor and temperature in gases?
Keeping volume at about 1 bar, CF can not be greater than 1. The real gas equation can be written in the given condition as (P + [a/(V^2)])*V = RT. This gives us CF = 1 - (a/(RTV)). If you keep on increasing temperature, CF will tend to 1, but it will never become exactly 1.