Recent content by iHEARTmath

Thank you:)

Sorry I don't understand, t=sv; t=25x0? t=0?

What is the formula that is needed to find the flight time for half of the journey?

Vf=Vi+-9.8x(25/Vi.cos30) 0=v-9.8x(25/v.cos30) v=9.8x(25/v.cos30) u∧2cos30=9.8x25 u∧2=(9.8x25)/cos30 u= square root((9.8x25)/cos30) u=16.8196799??

Ah.. what do I use the vertical height for? 25tan30= 14.43375673 so then, Uv=0 Height?=14.43375673

if s=0 it's simplified to u= (square root of 9.8x50)/cos30 and the answer is 23.78661943 but if s=50 the answer is 27.80110847 What is correct? and why? Please help

I tried working it out... Uv= usin30 Uh= ucos30 t= d/Uh, t= 50/ucos30 s=Uv.t+(1/2).-9.8∧2 and does s=0? I can't remember why. 0=usin30.(50/ucos30)+(1/2).-9.8.(50/ucos30)∧2 0=? how do i simplify this?

t= d/u, so t=d/ucos30. Do I leave it as that or.. t= 50/ucos30?

Could you give some advice in how I would do that? Like which formula to use? Can it be figured out using these formulas?

Homework Statement A golf ball is hit at an angle of 30 degrees, it travels 50m landing straight in the hole. Ignoring air friction, what is the initial velocity? Homework Equations not too sure, d=vi.t+1/2.a.ts∧2, vf=u∧2+2.a.d, v=u+a.t, d=u.t The Attempt at a Solution Vertical...