Recent content by IITSRII

thats a typo whats the force on E due on ion A

ah yeah they are so negative charges are attracting E since like charges repel they all cancel out since they are pulling away in opposite directions?

already drawn the picture, is it possible that 2 forces repel and 2 forces attract towards E hence 2 forces cancel out if the structure is square like ABCD with E in the middle of everything

Since electric force is KQ1Q2/r2 9*10^9*1.6*10^19*1.6*10^19 / 0.141^2 then multiply that answer by 4 because of the 4 ions would that be it?

If there's 2 charges involved wouldn't they have the same charge as they both are ions which lost electrons 9*10^9 * 1.6*10*-19 * 1.6*10*-19 / (0.141*10^-9)^2 =1.15*10^8 since F = KQ1Q2/d^2 For the net electric force on E would I perhaps sum the individual force of the other 4 ions onto E...

How would I find the net electric force on E I know F= KQq/r^2 but I think I might get confused with the previous answer not sure where to start from

Sorry about that 9*10^9 * 1.6*10*-19 / (0.141*10^-9)^2 = 7.24*10^10

Homework Statement This is the question Structure opposite comprises 5 ions each of which has lost one electron. The sides of the square formed by the 4 outer ions are of length 0.2nm Ion E is at the midpoint 1.What is the force on A due to ion A?Homework Equations I'd imagine: F= kq / r^2...