Recent content by illegalvirus

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    Hertz and polarization of EM waves

    Hi, I'm having difficulty understanding exactly how the reciever loop detects the EM waves in this experiment and I can't find any definitive information online. My understanding is that since EM waves are transverse, to be absorbed by the receiving electrodes, the length of the molecule chains...
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    Finding the Second Derivative of a Square Root Function

    I got this, \frac{3}{2}(3x-4)^{-0.5}-\frac{9}{4}x(3x-4)^{-1.5} But when finding the exact value of f''(2) I had a bit of a problem as well. So far I have, f''(2)= \frac{-9}{4\sqrt{2}} + \frac{3}{2\sqrt{2}}. =\frac{-6\sqrt{2}}{4\sqrt{2}} But the answer is...
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    Finding the Second Derivative of a Square Root Function

    Okay thank you, I've just realized that I've forgotten to multiply by the derivative of the brackets.
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    Finding the Second Derivative of a Square Root Function

    Wait, how did you get that?
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    Finding the Second Derivative of a Square Root Function

    Ahh, whoops. The original equation to derive is actually f(x)=x\sqrt{3x-4}!
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    Finding the Second Derivative of a Square Root Function

    Sorry, I think the first derivative is this, f'(x) = \frac{1}{2}x(3x -4)^{\frac{-1}{2}}
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    Finding the Second Derivative of a Square Root Function

    Somehow I got the same answer :confused: f'(x) = \frac{3}{2}x(3x -4)^{\frac{-1}{2}} f''(x) = \frac{-9}{4}(3x -4)^{\frac{-3}{2}}
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    Finding the Second Derivative of a Square Root Function

    Homework Statement Find the exact value of f''(2) if f(x)=\sqrt{3x-4} Homework Equations See above The Attempt at a Solution I've tried to use the product rule to differentiate. f= x(3x -4)^{\frac{1}{2}} f'= (3x -4)^{\frac{1}{2}} + \frac{3}{2}^{\frac{-1}{2}} f''=...
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