Recent content by imisschem

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    Cart on loop: velocity at top, normal force, and loss of contact

    Okay, that makes sense! Thank you very much!
  2. I

    Cart on loop: velocity at top, normal force, and loss of contact

    well actually for the most part yes. I'm just confused.. is there normal force at point A? because at the highest velocity i thought it canceled out. but i don't actually know.
  3. I

    Cart on loop: velocity at top, normal force, and loss of contact

    not really...
  4. I

    Cart on loop: velocity at top, normal force, and loss of contact

    nevermind, i got 2.05... calculator error
  5. I

    Cart on loop: velocity at top, normal force, and loss of contact

    Okay.. PE1 + KE1 = PE2 + KE2 mgh + 1/2mv^2 = mgh + 1/2mv^2 (.5kg)(9.8)(2) + .5(.5)(1.5)^2 = (.5)(9.8)(1.9) + .5(.5)v^2 9.8+ .5625 = 9.31 + .25v^2 v= 8.2?
  6. I

    Cart on loop: velocity at top, normal force, and loss of contact

    so.. I'm still confused. do i need to get the total energy first (by finding PE and KE and adding them), then account for Wnc because of friction, and THEN get the velocity?
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    Cart on loop: velocity at top, normal force, and loss of contact

    it could have been .5 kg, the diagram was so hard to read since it was a copy. the height of the second one i believe was 1.9, but, those numbers are so close and the diagram seemed off.. i don't know. i just like.. even without the numbers i have no idea how to solve the problem other than...
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    Cart on loop: velocity at top, normal force, and loss of contact

    Homework Statement In case the numbers are hard to read: Mass of the cart- .5g Initial Velocity- 1.5 m/s The height of the first hill is 2. Radius of the circle- .09m I need to find velocity (final, i think) force(s) on the cart at point A the magnitude of the force(s) at point...
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