I think I just realized what the X^2 is doing in this equation. When reactance is present in a circuit there is either a current or voltage lag. Because of this there will be a discrepancy between the voltages and currents across each of the components and the total voltage and current of the...
When you showed how to separate out the j (or imaginary parts) from the equation by multiplying by its complex conjugate I'm now left wondering what X^2 is representing here? It used to represent imaginary reactance but since there's no imaginary to it anymore, is it only whatever real...
So when we take the imaginary j parts from a reactance, what are we left with? Whatever real resistance it has? This would mean that every reactance contains at least some real resistance, which would make sense because every coil or capacitor must have at least some resistance. Is this correct?
First of all, thank you so much for taking the time to break this down for me DragonPetter!
Okay forgive me if this next question is kind of dumb. In the last equation, what is that fancy R you decided to multiply the whole equation by?
If you don't already know, this is an equivalent to conductance. What I can't figure out is why reactance (X) would have any place in this equation? Remember, we're talking about conductance here, not susceptance. In an equation for susceptance it would make sense... being that it's comprised...