Recent content by imranmeghji

the nth term for each is givn below: a(x): 3n b(y): 30-2n c(z): 11-0.5(n) so...z = 11-0.5(n) = (22-n)/2 = (22-4n+3n)/2 = (22-4n +x)/2 = (8+22-2n-2n+x-8)/2 = (30-2n-2n+x-8)/2 = (y+x-2n-8)/2 = y/2 + x/2 - n -4 = z

prove the folowing and state when the inequality holds... |x+y+z|<=|x|+|y|+|z| i was thinking that i consider all the possible cases, ie x is positive, y positive, z positive; then the various combinations with negative as well... is there another shorter method of doing it? help...