Recent content by Indira_Clueless

Thanks to both of you @Khashishi @haruspex :smile:

The height of OB would equal r - BC = r - cos(α) * r which you could also write as r * (1 - cos(α))

Ah sorry, wrong angle. :sorry: BC = cos (α) * r then, if my trigonometry doesn't fail me.

Ah and then I can use pretty simple trigonometry ... Yeah I think I get how this is a way.

I do know it can be, it depends on where you set the start point (for example of a movement. If I throw something down and I set the startpoint of the motion to where the fall started, then the height the object is gain would be negative). But my α would be negative too right? Since my...

I could calculate the upper part (positive part) of the height with sin(α) but I'm not sure what to do with the negative part :sorry:

@Khashishi if I set the general height of the circle to zero in the center, then the max height would be r and the starting height would be -r ?

@haruspex well I guess the length of BC would be √(CA2 - BA2) ? I mean, if I got you correctly ... /Edit: Which means the height would be r - BC ... right?

@haruspex To be honest, I don't know what you mean ... I'm sorry for being so supid at the moment, I'm just really feeling helpless and am apparently not able to comprehend easy questions. @Khashishi believe me, it took forever to come up with this bullshit (sorry)

Could you maybe help me calculate it correctly? I have been stuck for a while and probably miss the obvious (which I apologize for) /Edit: I can't really set the height of the middle of the loop to zero as it would alter the calculation for potential energy and by that alter the whole formula...

But how do I derive an equation for v(α) if not through trying to derive the height by α?

Homework Statement Task: [/B] On a friction free loop de loop, a object (m=600kg with passengers) moves with a velocity of vu = 120km/h at the lowest point of the loop. The loop has a radius of r=15m. The position of the object is given with the angle α. Derive the formula for the velocity...