The velocity (final) for the bus would have to be equal to the pedestrian (thinking out loud, stop me if I'm wrong). therefore V(f) = 6.0 m/s
You then use the equation v(f)^2 = v(i)^2 + 2ad
(6.0m/s)^2 = 2(1.0m/s/s) (d)...
pedestrian : velocity = 6.0m/s
Acceleration = 0 m/s/s (constant velocity, not sure if correct)
displacement = displacement of bus + 16m
time = same as bus
bus: acceleration = 1.9 m/s/s
V(initial) = 0m/s...
Haha, the problem is that I have a similar question sitting in my locker at school, and this question is due tomorrow, I'm just so confused, because I seems like the answer is right there. I have many equations to work with, but I seem to have 2 variables for both the bus and the pedestrian. If...
I'm in a pickle with this question. Turning to anyone who can help me please.
A pedestrian is running at his maximum speed of 6.0 m/s trying to catch a bus that is stopped at a traffic light. When he is 16 m. from the bus, the light changes and the bus pulls away from the pedestrian with an...