Recent content by itryphysics

can someone please help?!?

ok thanks! but my answer is coming out to be a negative .. (6.63 e^-34)(670E-9)= 1.2 (6.63e^-34)(522e^-9) - 0.2W 4.4421e^-40 = 4.15303 e^-40 -0.2W 2.8907e^-41 = -0.2W this makes W negative.. help please =(

So... KE = hf - W then after substitution .. hf = 1.2 (hf - W) + W hf = 1.2 hf -1.2W + W -0.2 hf = -0.2 W since f=c/lambda 0.2 hc / lambda =0.2 W right?

eeeek ...not sure .. can you get me started at least , please.

sorry still a bit confused. Do I not take KE into account at all? wht do i do with the 1.2?

I don't have the KE of red. So wht do i multiply 1.2 by?

hf = KE + W and hf = 1.2KE + W ?

6.63e^-34 (3e^8) / (522e^-9) = 1.2 + W 7.8 e^-19 = 1.2 + W 7.8 e ^-19 - 1.2 = W W= 1.2 (since 7.8 e^-19 is almost equal to zero) help =(

Yes I did that. But its the work function that I need. everytime i had 1.2 on the left side of the equation , the work function equalled 1.2 Please, can you provide any further help?

Homework Statement Red light of wavelength 670 nm produces photoelectrons from a certain material. Green light of wavelength 522 nm produces photoelectrons from the same material with 1.2 times the previous maximum kinetic energy. What is the material's work function? answer in units of eV...

so for my answer i got 48.7 which was correct. Now i need to find the angle of dispersion of visible light with the same angle of incidence . So i found the angle of deviation for the violet light which was 52.27. then i subtracted the two to get the anglular dispersion which came out to be...

Homework Statement The index of refraction for violet light in silica flint glass is 1.65 and for red light is 1.62.What is the angle of deviation for the red ray passing through a prism of apex angle 59.7 degrees. If the angle of incidence is 47.4 degrees. Homework Equations nglass...

im lost. sorry . so what is wrong with the way i was calculating theta 1?

concave mirror! Homework Statement The real image produced by a concave mirror is found to be 0.756 times the size of the object. If the distance from the mirror to the screen on which the image appears is 0.764 m , what is the focal length of the mirror? Homework Equations (a) 1...

so everything i did was ok except for I use inverse of tan and not sin to find the angles?