Recent content by iviv

Hmm. So, assume 10Kn loads, and a beam 3m long. Since its symmetrical, the moments would be 10Kn at each support. The force is 10Kn at 1/3 of the beam, so at the centre it would be 15. Using the equation, 15=WL/x 15= 20*3/x x=4 So the equation would be WL/4, which makes it the same as the...

Hi again. First, I'd like to say thanks a ton to tiny-tim for helping me through with my last problem. He was a great help, though I didn't want to bump that thread to say thanks. Anyway, I've got a far simpler issue now, and I'm having a brain fart. 1. A simply supported beam of span, L...

Oh god, its a rounding error, isn't it? XD Well, that makes things add up a whole lot better now! Thanks!

Yeah it is, but that doesn't change any of the maths in those equations, does it? I mean, you use sin to resolve horizontally, and cos to resolve vertically?

Thanks for the welcome, but oh dear, I think you've lost me there! You're saying that the equations are right, and it does equal zero, so the member isn't in compression or tension?Also, a related question I'm trying to get my head around. I think I'm doing it right, but I seem to have an answer...

Hi all, been here several times and found good help for several questions, but this time I'm out of luck, so here I go. Homework Statement By taking a section through the pin-jointed frame as shown, and considering the quilibrium of the structure to either the left or right of the section...