Recent content by IvyCap

I think I may have gotten the last part v=dx/dt v dt = dx ∫v dt= ∫dx ∫(10-t)/(1+2t) dt = ∫dx t=0 to 10 and x=0 to x and this is where my integration is so bad I get stuck.

-->A particle is slowing down from initial velocity v_0=10 with acceleration a=-(1+2v), where v is velocity. Find a) v(t) b) time to stop c) stopping distance What I have so far A) V=Vo+at v=10+(-1-2v)t v+2vt=10-t v(1+2t)=10-t v(t)=(10-t)/(1+2t) B) V=0m/s at stop 0=(10-t)/(1+2t)...