Recent content by j_reez

Thank You thanks guys! its very clear to me now :) my book had one very limited example which made it sound like i only need to make one substitution. however, i clearly see it now! thanks, Justin

i don't see how that would work...if u=xy' then du/dx=y' +xy'' how would thos substitutions work?

this problems driving me crazy

this is the problem: xy'' -x(y')^2 = y' my book says that i need to substitute u=y' and du/dx=y''... so i get: x(du/dx)-xu^2 = u so next the book says i need to separate the x's/dx' to one side and u's/du's to the other. however, i cannot do it am i using the correct technique...

im really not seeing how this can be separated

yes that was the form it was in. I've got it down to this: [int]dx/x = [int]du/(u(u+1)) how do i integrate the RHS?

ok hows this look: x(du/dx) -u^2 = u x(du/dx) = u + u^2 (1/x)dx = (1/u+u^2)du ?

i must be making a trivial algebraic mistake...as far as i know I am supposed to be isolating dx's and x's on one side with u's and du's on the other...which is why i divided through by x. is this not allowed? oh boy, i see it...i can't get dx to the other side like that...let me see what i...

problem: xy'' -x(y')^2 = y' what i have so far: u=y' and du/dx=y'' du/dx - u^2 = (1/x)u int[(1/u)-u]du = int[1/x]dx ln u - (1/2)u^2 = ln x +c ok, now is what I've done so far correct? what do i do next? ps: i'd like to say hi to everyon :) I am new here