Recent content by jacc

Thanks a lot for the help :biggrin:

are the 5 resistors touching any 1 vertex in parallel? so the opposite vertex would have the same situation. which would leave 10 resistors in the middle also connected in parallel? then these 3 groups would all be connected in series? so if what i am thinking is true then the total resistance...

This brings me back to my original problem, as i have no idea how to reduce this circuit. I can't tell which are in series and which are in parallel.

So each of the vertices has 5 resistors connected to it. Which means if a voltage source was connected to one of these vertices, then 5/12 amps would flow through each resistor. Then each of those resistors is connected to 4 more. but of those 4, two are connected to each other so they can't...

Homework Statement Consider an icosahedron all of whose edges are 2 ohm resistors. If a 12 V battery is connected in opposite vertices, what is the current flow through each resistor? Homework Equations v=ir The Attempt at a Solution I found somewhere that the equivalent...