Recent content by Jackie Treehorn

Torque = lever arm x force so just for just the 300g at 0cm to 20cm would be .3kg x .2m = .06, but wouldn't I need to include the 20cm of beam weight as well?

equal weight on both ends, and a net torque of zero. I just don't know how to show this in equation form.

so the cog would be at 50cm, how would I devise an equation to solve for this, and how does the cog play a part in solving for the weight of the beam

the COG should be at 10cm on the left and 60cm on the right, but I still have no clue as to what equation I should be using to determine the weight of the full beam. I understand the right portion of the beam must equal the left portion of the beam plus the 300g. I've gotten as far as knowing...

Homework Statement I have a 100cm beam with the fulcrum at the 20cm point. At the 0cm point is 300g which puts the beam into balance. Homework Equations How can I find the total weight of the beam and the torque due to the weight of beam using the given information.The Attempt at a...