Recent content by jacko12

Okay I think I have figured it all out. So part A. Use Ix=bh^3/12 with corresponding values. The use M=f*Ix/y to find moment then M=PL/4 to find load. Then part B. to find the deflection use D=PL^3/48EI. Then part c. Was bit tricky not 100% frist of all found the ration of E values of the 2...

mm okay i will have to have good look. but I mean i can do these questions. I am just not sure how to approach it cause I am use to using the self weight formula in the process. Havent done a question like this. Hence why I posted it for help not to get another question from my own questions

can i just use the Mmax= PL/4? Also for question b/c I am not sure what formulas to use cause all the deflection involve self weight.

Only question is now i think I found formula to use. stress (f) = P/A to find the load. what is the A area? of just the timber obviously but the cross section area of just L*w?

oh yes. That makes total sense I just skip the step of self weight to find the max moment then to find the stress. Instead I sub in the given max stress of 10MPa in f= My/Ix equation to find the max moment.

hhhh

thanks

so what formula will be used to find the Load? that's what's stunted me

mm I am still bit confused will have to sit down again and work on question.

by using the equation f= My/Ix Yeah Iam not sure how I approach the question so I worked out serval unknowns. I thought the 10Mpa was relevant for question C.. As the steel plates are not added yet?

[b]1. Homework Statement [b/] A timber beam, with rectangular cross section (h × b) is reinforced with additional full width (b) steel plates. There is a plate of thickness t securely connected on the bottom and a plate of thickness 2t on the top of the timber to ensure composite action in...