Recent content by Jadon

Awesome. So replacing that junk with 0, which I "kind of" solved for/set equal to, allows for me to use 0 in the dy/dt equation which gives dy/dt = 27π(cos(0)), which is equal to 27π. Seems logical.

cos(theta) would equal 1 then, so the maximum vibration speed would be equal to 27π cm/s or rad/s (not quite sure on the units anymore lol).

That would tell me that sin-1(0) = 5πcm-1x + (3π rad/s)t - π/8 . This in turn would tell me that π/8 = 5πcm-1x + (3π rad/s)t and that 1/8 = 5cm-1x + (3rad/s)t. I'm just not sure what direction I should be going, what I am truly solving for.

I understand what you are asking, but I don't understand how to obtain any information from this. From dy/dx = 27π(cos((5πcm-1)x + (3π rad/s)t - π/8) I can't seem to draw any numerical information. Could I get a hint to get in the right direction?

Well if you were to use the second derivative, the sin function would equal 0, so maybe the cosine function equals 1?

So the velocity would be dy/dt, and to get this, take the derivative with respect to t, getting: dy/dt = 27π(cos((5πcm-1)x + (3π rad/s)t - π/8) This gives velocity (but still has x and t in it). Wouldn't I have to set the second derivative equal to zero to find the maximum velocity?

dx/dt would, if that's what you are asking...but it moves in the y direction. I'm a bit confused on that...

Ok so, to find this speed, I would take the derivative of the function as one would do when doing this for oscillations, correct? I just am not sure how to do this with variables x and t inside the cosine. Or am I going the wrong direction?

Ok then, I see what you mean. I believe it means the maximum speed of the element of string. So the speed as the element is at y = 0.

The only thing I could think of was taking the derivative of the original equation (not sure whether with respect to x or t) and then setting equal to zero and solving for v (probably with respect to x then) but I would still be stuck with another variable.

Homework Statement y(x,t) = (9.00cm)sin((5Πcm-1)x + (3Π rad/s)t - Π/8) There are 11 parts, and I have answered the first 10 (they include velocity of a wave, amplitude, all that good stuff), but I haven't seen anything in lecture or in the textbook that mention finding maximum vibration speed...